Question

se dau numerele complexe
z1=5-2i
z2= 3+i
se se calculeze
1) z1+z2, 2)z1-z2, 3)z1 ori z2, 4)z1 supra z2

Answer 1

1) 5-2i + 3+i = 5+3 -2i+i = 8 -i

2) 5-2i - 3-i = 2 -3i

3) (5-2i)(3+i) = 15+5i -6i-2i² =  15-i-2*(-1) = 15-i+2 = 17-i

4) (5-2i)/(3+i) amplifici cu 3-i = (5-2i)(3-i)/(9-i²) = (15-5i-6i+2i²)/(9+1) = (15-11i-2)/10 = (13-11i)/10