Question

Se dau numerele:
m=(160-30×5)×12-6-(24+6÷6)
n=32÷8+3×[60+8×(200÷5-36÷2)]
Repere pls.

Answer 1

$m=(160-30 \cdot 5) \cdot 12-6-(24+6:6)$

= (160-150)×12-6-(24+1)

= 10×12-6-25

= 120-6-25

= 114-25

= 89

$n=32:8+3 \cdot [60+8 \cdot (200:5-36:2)]$

= 4+3×[60+8×(40-18)]

= 4+3×(60+8×22)

= 4+3×(60+176)

= 4+3×236

= 4+708

= 712