Question

Se dau numerele:
x=3*7x9*2:[2*2-(27*5+10*10)*0]*10=
y=5*10:5*8-5:5-3*100:9*50-2*50^0=
A)calculati x si y
B)comparati (x+y)*2000 cu 2*4000


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Answer 1

x=3*7x9*2:[2*2-(27*5+10*10)*0]*10=
=3*7x3*4:(2*2-1)*10=
=3*11:(4-1)*10=
=3*11:3*10=3


y=5*10:5*8-5:5-3*100:9*50-2*50^0=
=5*2-1-3*100:3*100-2*1=
=5*2-1-1-2*1=
=25-4=21

(x+y)*2000 =(3+21)*2000 =24*2000
2*4000=(2*2)*2000=4*2000
24>4    deci   (x+y)*2000 > 2*4000