Question

Se descompun 300 g de carbonat de calciu.Cate grame de oxid se obtin si cati moli de dioxid de carbon rezulta?
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Answer 1

m=300gCaCO3
CaCO3=>CaO+CO2
MCaCO3=ACa+AC+3AO=40+12+3×16=100g
MCaO=ACa+AO=40+16=56g
100gCaCO3.....56gCaO
300gCaCO3.......x
x=300×56/100
x=168gCaO
MCO2=AC+2AO=12+2×16=44g
n=m/M
n=300/100
n=3moli
1molCaCO3.....1molCO2
3moliCaCo3....y
y=3×1/1
y=3moli