Question

Se descompun 310 g de carbonat de calciu cu 20% impuritati ce volum de gaz se degaja

Answer 1

M,CaCO3=100g/mol
Vm= 22,4l/mol

calcullez masa si moli CaCO3 pur, stiind puritatea 80%
p= m,purx100/m,impur
80=m,purx100/310---->m,pur=248g

n=m/M= 248g/100g/mol= 2,48mol



1mol.............................1mol
CaCO3--------> CaO  +  CO2
2,48mol........................x=2,48mol

V= nxVm= 2,48molx22,4 l/mol=.....................calculeaza !!!