Question

Se neutralizeaza 4l de solutie de aminoacid monocarboxilic care contine 35,95% oxigen, cu 150ml de solutie de NaOH 2M.Care este denumirea si concentratia molara a aminoacidului?
a)valina, 1M; b)alanina,0,075M; c)glicina, 0,5M; d)acid α-aminopropanoic, 0,05M;
e)acid aminoacetic, 0,075M;

Answer 1

Fiind monoaminomonocarboxilic are formula generala: CnH2n+1NO2
M.....................100%
32g...............35,95%
M=3200/35,95=89g/mol
M=12n+2n+1+14+16×2=14n+47=89
14n=42 => n=3 => alanina
n=Cm*Vs=2*0,15=0,3moli
1mol...................1mol
C2H6N-COOH + NaOH -> C2H6N-COONa + H2O
x=0,3moli..........0,3moli
Cm=n/Vs=0,3/4=0,075M
b)