Question

Se stie ca (7la puterea4+7la putera 5 ).49=x la puterea 3 . Atunci .Si in plus {2.3la puterea2-3 la puterea 2+3. [3+3 (3la puterea3-3la puterea5:3la puterea3)]}:(17la puterea0+0la putera2014+3la puterea1)=...Repede plz.

Answer 1

(7^4+7^5 ) ×49=x^3
7^4(7^0+7^1 ) ×7^2=x^3
(7^4(1+7) ×7^2=x^3
7^6 * 8=x^3
(7^2)^3 * 2^3=x^3
(7^2 * 2)^3=x^3
x=7^2 * 2
x=49*2
x=98

{2×3^2-3^2+3×[3+3×(3^3-3^5:3^3)]}:(17^0+0^2014+3^1)=
={2×3^2-3^2+3×[3+3×(3^3-3^2)]}:(1+0+3)=
={3^2+3×[3+3×3^2(3^1-3^0)]}:4=
=[3^2+3×(3+3×3^2 ×2)]:4=
=(3^2+3^2+3^4 ×2):4=
=3^2×(3^0+3^0+3^2x2):4=
=3^2×(1+1+18):4=
=3^2×20:4=
=(9×5=45