Question

Se stie ca a =11 si b+c=8 .Calculati : 10×a+9×b+9×c! 7×b+7×c+9×a! 11×b+a×c.

Answer 1

$a = 11$

$b + c = 8$

$10 a + 9b + 9c = 10a + 9(b + c)$

$= 10 \times 11 + 9 \times 8$

$= 110 + 72$

$= 182$

$7b + 7c + 9a = 7(b + c) + 9a$

$= 7 \times 8 + 9 \times 11$

$= 56 + 99$

$= 155$

$11b + ac = 11b + 11c = 11(b + c)$

$= 11 \times 8 = 88$