Question

Se stie ca a=11 si b+c=8 . Calculati:
a) a ori b+a ori c=
b) 2 ori a+3 ori b+3 ori c=
c) 10 ori a+9 ori b+9 ori c=
d) 11 ori b+11 ori c-6 ori a=
e) 3 ori a-3 ori b-3 ori c =

Answer 1

Vom folosi la toate metoda factorului comun:
a)ab+ac=
a(b+c)=
11×8=88
b)2a+3b+3c=
2×11+3(b+c)=
22+3×8=
22+24=46
c)10a+9b+9c=
10×11+9(b+c)=
110+9×8=
110+72=182
d)11b+11c-6a=
11 (b+c)-6×11=
11×8-66=
88-66=22
e)3a-3b+3c=
3×11-3(b+c)=
33-3×8=
33-24=9