Question

se stie ca a=11 si b+c=8. calculati: cele taiate numai trebuie ​

Answer 1

d. ab + ac + 25 = a(b + c) + 25 = 11 × 8 + 25 = 88 + 25 = 113

e. ab + ac - 34 = 88 - 34 = 54

f. 7b + 7c + 9a = 7( b + c ) + 9a = 7 × 8 + 9 × 11 = 56 + 99 = 155

g. 11b + 11c - 6a = 11( b + c ) - 6a = 11 × 8 - 6 × 11 = 88 - 66 = 22

h. 3a - 3b - 3c = 3( a - ( b + c )) = 3 × ( 11 - 8 ) = 3 × 3 = 9

i. 11b + ac = 11b + 11c = 11( b + c ) = 11 × 8 = 88

Answer 2

d)11•8+25=113
e)11•8-34=54
f)7•8+9•11=155
g)11•8-6•11=22