Question

se stie ca a=11si b+c=8
calculati
ab+ac
2a+3b+3c
10a+9b+9c
ab+ac+25
ab+ac-34
7b+7c+9a

Answer 1

- a(b+c) = 11*8=88
- 2a+3(b+c) = 2*11+3*8=22+24=46
- 10a+9(b+c) = 10*11+9*8=99+72=171
- a(b+c)+25=11*8+25=88+25=113
- a(b+c)-34=11*8-34=88-34=54
- 7(b+c) +9*11= 7*8+99=56+99=155

Answer 2

A(B+c)=11*8=88 2*11+3(B+c)=22+24=46 10*11+9(B+c)=110+72=182 A(B+c)+25=88+25=113 A(B+c)-34=88-34=54 7(B+c)+9*11=56+99=155