Question

Se ştie ca a=5 şi b+c=12 aflaţi:2a+b+c;8c+7a+8b;12a-(2b+2c);3a+b+c;ab+ac;5b+8a+5c;35+a-(2b+2c (

Answer 1

Pai 2a+b+c=5x2+12=22
8c+7a+8b=7a+8(b+c)=7x5+8x12=35+96=131
12a-(2b+2c)=12a-(2x(b+c))=12a-2x12=12x5-24=60-24=36
3a+b+c=3x5+12=27
ab+ac=a(b+c)=5x12=60
5b+8a+5c=8a+5b+5c=8x5+5(b+c)=40+5x12=100
35+a-(2b+2c)=40-(2x(b+c))=40-2x12=40-24=16
Gata! :)

Answer 2

a=5
b+c=12
2a+b+c=2×5+12=10+12=22
8c+7a+8b=7a+8 (b+c)=7×5+8×12=
=35+96=131
12a-(2b+2c)=12×5-2×(b+c)=60-2×12=
=60-24=36
3a+b+c=3×5+12=15+12=27
ab+ac=a×(b+c)=5×12=60
5b+8a+5c=8×5+(5b+5c)=40+5×12=
=40+60=100
35+a-(2b+2c)=35+5-(2×12)=40+24=64