Question

Se stie ca a-b=873 ; a:b=12 rest 15 ; 5b=3c.
Sa se afle a+b+c.
REEEPEDDEEEEE

Answer 1

$a=b+873$
$a:b=12 rest15 =\ \textgreater \ a=12b+15$
Egalam expresia lui a din ambele ecuatii si rezulta:
$b+873 = 12b + 15$
$11b=858$
$b=78$
$a=b+873=78+873=951$
$5*b=3*c =\ \textgreater \ 5*78 = 3*c =\ \textgreater \ c= \frac{390}{3} =130$
$a+b+c= 78 + 951 + 130 = 1159$