Question

se stie ca axb=17,25 ci c=0,2.calculati
1)ax(bxc)
2)axb+c
3)axb-c

Answer 1

1)ax(bxc)=axbxc=17,25x0,2=3,45

2)axb+c = 17,25+0,2= 17,45
3)axb-c = 17,25-0,2= 17,05