Question

Se sulfoneaza benzenul cu o solutie de h2so4 de concentratie 90% si se obtin 20 moli de acid benzensulfonic si 2,5 moli de acid benzendisulfonic . Masa solutiei de h2so4 consumata este

Answer 1

2C6H6 + 3HO-SO3H -> C6H5-SO3H + C6H4-(SO3H)2 +3H2O
Cp=90%
nC6H6SO3=20 moli
nC6H4-(SO3H)2=2.5 moli
MC6H6SO3=12*6+6+32+16*3=158g/mol
MC6H4-(SO3H)2=12*6+6+32*2+6*16=238g/mol
n=md1/M =>md1=n*M=20*158=3160g
n=md2/M =>md2=n*M=2.5*238=595g
mdf=md1+md2=3160+595=3755g
Cp=mdf/msf*100 => msf=md*100/Cp=3755*100/90=4172.22g solutie H2SO4 ?

Answer 2

C6H6 +HOSO3H----> C6H5SO3H+H2O
            20mol......           20mol
C6H6+2HOSO3H-----> C6H4(SO3H)2 + 2H20
              5mol........................2,5mol
n= 25mol H2SO4
m= 25molx 98g/mol= 2450gH2SO4
90/100= 2450ms------------------> ms =