Question

Se supun fermentatiei acetice 500g etanol 46%. Se cere randamentul transformarii, daca solutia finala contine 5% etanol.

Answer 1

masa de etanol pur
m= 500gx0,46= 230g
n(niu)= m/M---> n= 230g/46g/mol= 5mol etanol
1mol                     1mol
C2H5OH +O2---> CH3COOH+H2O
5mol........................5mol
m,acid= 5molx60g/mol= 300g
100g amestec.......5g alcool.........95g acid
                             x.........................300g
x,masa de alcool netransformat= 15,79g----. >
m,alcool transformat= 230-15,8g =214,2g
eta= 214,2x100/ 230=...........................calculeaza!!!!!