Question

Se supun nitrarii totale 460 kg de toluen, de puritate 80%.Calculati mada de 2,3,4-trinitrotoluen obtinuta, exprimata in kilograme.

Answer 1

p/100=mpura/mimpura => mpura=p*mimpura/100=80*460/100=368kg toluen (pe reactie niciodata nu lucram cu masa impura. cand stim masa reactantului si puritatea, calculam masa pura)
92kg......................227kg
C7H8 + 3HNO3 ->C7H5(NO2)3 + 3H2O
368kg....................x=?
x=368*227/92=908kg TNT