Question

Se supun reactiei 4,8g Mg cu oxigenul. Calculati cantitatea (g,moli) de oxid de magneziu care se formeaza. DAU COROANA! URGENT!

Answer 1

Răspuns:

MMg=24g/mol

MMgO=24+16=40g/mol

2×24 2×40g

2Mg + O2=> 2MgO

4,8g xg

x=4,8×2×40/2×24=8 gMgO

n=4,8/24=0,2 moli Mg

2moli 2moli

2Mg + O2=> 2MgO

0,2moli ymoli

y= 0,2×2/2=0,2 moli MgO