Question

Se supun reducerii cu H2 200 g butanona de puritate 68%. Calculeaza masa de compus hidroxilic obtinut si volumul de hidrogen (c.n.) consumat

Answer 1

P/100=mpura/mimpura => mpura=p*mimpura/100
mpura=68*200/100=136g butanona
72g........22,4l......74g
C4H8O + H2 -> C4H10O
136g......x=?........y=?
x=136*22,4/72=42,31l H2
y=136*74/72=139,77g 2-butanol