Question

Se supune analizei elementale o subst organica constituita din carbon,hidrogen,oxigen si sulf. La analiza elementala cantitativa a 0.632 grame de subst s-au obtinut urm rezultate: 1.056 g CO2,0.216 g H2I si 0.932 g BaSO4. Stiind ca subst contine un atom de sulf in molecula,sa se det formula moleculara a subst

Answer 1

44 g CO2........12 g C
1,056 g CO2.......x g C
x = 0.288 g C
18 g H2O........2 g H
0,216 g H2O.......y g H
y = 0.024 g H
233 g BaSO4........32 g S
0.932 g BaSO4.......z g S
x = 0.128 g S
m O = 0.632 - 0.288 - 0.024 - 0.128 = 0.192 g oxigen
0.288/12 = 0.024
0.024/1 = 0.024
0.128/32 = 0.004
0.192/16 = 0.012
Imparti la 0,004 => FM: (C4H4SO2)n
Substanta contine 1 atom de sulf => n = 1 => C4H4SO2