Question

Se trateaza 150 g de solutie de acid clorhidric de concentratie 36,5% cu 200g de solutie de hidroxid de sodiu. Considerand reactia totala , determina:
-concentratia procentuala a solutiei finale
AJUTOOR VA ROOG

Answer 1

Răspuns:

c=mdx100/ms---> m,HCl= cxms/100==36,5x150/100g=54,75g

                              m,apa= ms-md= 150g-54,75g=95,25g

miu,HCl= 36,5g/mol

niu,HCl= m/miu= 54,75/36,5mol=1,5mol

1,5mol---> 1,5mol.......1,5mol,,,,,,,,1,5mol

HCl     +  NaOH ----> NaCl  + H2O

miuNaOH=40g/mol-------> m=niuxmiu-1,5x40g=60g

mapa=ms-md= 200g-60g=140g

miu apa=18g/mol------> m= 1,5x18g=27g

miu,NaCl=58,5g/mol-----> m=1,5x58,5g=87,75g=md

solutia rezultata contine 87,75g NaCl dizolvata in masa de apa care a rezultat din solutie adunata cu masele de apa de la cele doua solutii, de HCl si NaOH

m,apa= 27+ 95,25+ 140=>262,25g

ms=md+m,apa= 87,75+262,25=>350g

c=mdx100/ms= 87,75x100/350=>25%

Explicație: