Question

Se tratează cu acid sulfuric 800 g Cu .
a) masa acidului consumat = ?
b) masa sării obținut = ?
c) masa si volumul gazului degajat = ?

Answer 1

Cu + 2H₂SO₄ ⇒ CuSO₄ + SO₂ + 2H2O

Cu⁰ +2e⁻⇒ Cu⁺² se reduce (ag.ox) ||2||1

S⁺⁶ -2e⁻⇒ S⁺⁴ se oxideaza (ag.red) ||2||1


a) MCu=64g/mol

MH2SO4=2AH+AS+4AO=2*1+32+4*16=98g/mol

MCuSO4=ACu+AS+4AO=64+32+4*16=160g/mol

MH2=2AH=2*1=2g/mol

64g Cu.......................98g H2SO4
800g Cu......................xg

x=98*800/64= Calculeaza !!

b) 64g Cu..........................160g CuSO4
800g Cu................................xg

x=160*800/64=Calculeaza!!

c) 64g Cu.................................2g H2
800g Cu...................................xg

x=2*800/64=Calculeaza !!!

64g Cu.................................Vm=22,4L H2
800g Cu.................................xL

x=22,4*800/64= Calculeaza !!!