Question

Se trateaza o solutie de clorula de fier (FeCl3) cu o solutie de NaOH ce contine 160 grame de soda .Care sunt produsii de reactie si in ce cantitati se obțin. VAA ROOOOG

Answer 1

FeCl3 + 3 NaOH = 3 NaCl + Fe(OH)3
M NaOH = 23+1+16 = 40
M NaCl = 23+35,5 = 58,5
M Fe(OH)3 = 56+3*(1+16) = 107
3*40 g NaOH........3*58,5 g NaCl..........107 g Fe(OH)3
160 g NaOH.................x................................y
x = 234 g NaCl
y = 142,666 g Fe(OH)3