Question

Si de aceasta va rog mult e urgent dau si coroana

Answer 1

a) pH = 4

HCl -> Acid tare ⇒ [HCl] = C = [H₃O⁺] = $10^{-pH}$ = 10⁻⁴ M

b) pH = 10

pH + pOH = 14 => pOH = 4

NaOH - B.T(baza tare) ⇒ [NaOH] = C = [OH⁻] = $10^{-pOH}$ = 10⁻⁴ M