Question

Simplifică,adu la același numitor și efectueaza:
A) 10 supra 15 + 6 supra 9
B) 3 supra 24 + 3 supra 12 + 5 supra 10
C) 4 supra 36 + 5 supra 15
D) 14 supra 30 - 6 supra 15 + 4 supra 12
E) 9 supra 30 + 4 supra 20 - 7 supra 14
F) 6 supra 28 + 6 supra 12 - 10 supra 35

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Answer 1

$\frac{10}{15}+ \frac{6}{9}= \frac{2}{3} +\frac{2}{3}=\frac{4}{3}$

$\frac{3}{24}+\frac{3}{12}+\frac{5}{10}= \frac{1}{8}+\frac{1}{4}+\frac{1}{2}=\frac{1+2+4}{8}=\frac{6}{8}=\frac{3}{4}$

$\frac{4}{36}+\frac{5}{15}= \frac{1}{9}+\frac{1}{3}=\frac{1+3}{9}=\frac{4}{9}$

$\frac{14}{30}-\frac{6}{15}+\frac{4}{12}=\frac{7}{15}-\frac{2}{5}+\frac{1} {3}=\frac{7-6}{15}+\frac{1}{3}=\frac{1}{15}+\frac{1}{3}=\frac{1+5}{15}=\frac{6}{15}=\frac{2}{5}$

$\frac{9}{30}+\frac{4}{20}-\frac{7}{14}=\frac{3}{10}+\frac{1}{5}-\frac{1}{2}=\frac{5}{10}-\frac{1}{2}=\frac{1}{2}-\frac{1}{2}=0$

$\frac{6}{28}+\frac{6}{12}-\frac{10}{35}=\frac{3}{14}+\frac{1}{2}-\frac{2}{7}=\frac{3+7}{14}-\frac{2}{7}=\frac{10}{14}-\frac{2}{7}=\frac{5}{7}-\frac{2}{7}=\frac{3}{7}$