Question

simplifica rapoartele 8x la puterea 3 supra 24x la puterea5 6xsupra 2(x+6) (x-1)(x+2) supra (x+2)(x+3) 4x(x-5) totul la puterea2 supra(x+1)(x-5)

Answer 1

$\frac{8x^{3}}{24x^{5}}$→ $\frac{1}{3^{5}}$

$\frac{6x}{2(x+6)}$→ $\frac{6x}{2x+12}$→ $\frac{1}{4}$

$\frac{(x-1)(x+2)}{(x+2)(x+3)}$→ $\frac{x-1}{x+3}$

$\frac{[4x(x-5)]^{2}}{(x+1)(x-5)}$→ $\frac{(4x)^{2}}{x+1}$→ $\frac{16x^{2}}{x+1}$

Sper să te ajute! ^_^