Question

Simplificati fiecare fractie astfel incat sa devina ireductibila:18/15,48/42,12/18,105/75,49/56,165/105

Answer 1

18/15 (3 = 6/5
48/42 (2=24/21(3=8/7
12/18(2=6/9(3=2/3
105/75(5=21/15(3=7/5
49/56(7=7/8
165/105(5=33/21(3=11/7

Answer 2

$\frac{18}{15}$ se simplifică prin 3 → $\frac{6}{5}$

$\frac{48}{42}$ se simplifică prin 6 → $\frac{8}{7}$

$\frac{12}{18}$ se simplifică prin 6 → $\frac{2}{3}$

$\frac{105}{75}$ se simplifică prin 15 → $\frac{7}{5}$

$\frac{49}{56}$ se simplifică prin 7 → $\frac{7}{8}$

$\frac{165}{105}$ se simplifică prin 15 → $\frac{11}{7}$