Question

Simplificati fractia 6+12+18+....+96 supra 8+16+24...+128
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Answer 1

$\displaystyle \frac{6+12+18+...+96}{8+16+24+...+128} = \frac{6(1+2+3+...+16)}{8(1+2+3+...+16)} = \frac{6}{8} = \frac{3}{4}$