Question

simplificati fractia ab + ba supra 3a+3b si simplificati fractia 1+2+3+....+2018 supra 2+4+6+....+2018 URGENTTT
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Answer 1

$\it \dfrac{\overline{ab}+\overline{ba}}{3a+3b}=\dfrac{10a+b+10b+a}{3(a+b)}= \dfrac{11(a+b)}{3(a+b)}=\dfrac{11}{3}$