Question

simplificati fractia algebrica x^2-1 supra x^2-3x-4"

Answer 1

$\frac{x^2-1}{x^2-3x-4} = \frac{(x-1)(x+1)}{x^2-4x+x-4}=\frac{(x-1)(x+1)}{x(x-4) + x-4} =\frac{(x-1)(x+1)}{(x-4)(x+1)}=\frac{x-1}{x-4}$