Question

simplificati fractia apoi scoateti intregii din fractia ireducdibila obtinuta 45pe35 65pe39 77pe33 120pe50 100pe75 810pe180

Answer 1

/=fractie,supra

45/35=9/7=1 intreg si 2/7
65/39=1 intreg si 26/39
77/33=(7x11)/(3x11)=7/3=2 intregi si 1/3
120/50=12/5=2 intregi si 2/5
100/75=4/3=1 intreg si 1/3
810/180=81/18=9/2=4 intregi si 1/2

Answer 2

45/35=9/7=1 intreg si 2/7
65/39=1 intreg si 26/39
77/33=(7x11)/(3x11)=7/3=2 intregi si 1/3
120/50=12/5=2 intregi si 2/5
100/75=4/3=1 intreg si 1/3
810/180=81/18=9/2=4 intregi si 1/2