Question

Simplificati fractiile :
1212 supra 2121
2+4+6+.......+50 supra 3+6+9+.......+75

Answer 1

$\frac{1212}{2121}= \frac{12*100+12}{21*100+21}= \frac{12*101}{21*101}= \frac{12}{21}= \frac{4}{7}. \\ \\ \frac{2+4+6+...+50}{3+6+9+...+75}= \frac{2(1+2+3+...+25)}{3(1+2+3+...+25)}= \frac{2}{3}.$

Answer 2

1212/2121=404/707=4/7

2+4+6+...+50/3+6+9+...+75=2 (1+2+3+..+25)/ 3(1+2+3+...+25)   =2/3