Question

Simplificati fractiile astfel incat sa devina ireductibile:4 pe 10..............28 pe 84...........333 pe 444...........25 pe 3250 ...........2x5x7 pe 3x5x11............2 la puterea a 3a  pe 2 la puterea a 5-a5 la puterea  a 4a x 7 la 3 x 11 la 4..............5 la 6 x 7x 11 la 3..............3a+6b pe 5a+10b .................9a+3pe 12a+4

Answer 1

4/10⁽²=2/5
28/84⁽⁷=4/12⁽⁴=1/3
333/444⁽¹¹¹=3/4
25/3250⁽²⁵=1/130
(2x5x7)/(3x5x11)=14/33
2³/2⁵=1/2²=1/4
5^(3x7³x11⁴)/5^(6x7x11³)=5^(7²x11)/5²=5⁴⁹ˣ¹¹⁻²=5⁵³⁷
3a+6b/5a+10b=3(a+2b)/5(a+2b)=3/5
9a+3/12a+4=3(3a+1)/4(3a+1)=3/4