Question

simplificați fracțiile, astfel încât să devină ireductibile: ​

Answer 1

$\frac{\cancel{{15}}^{(5}}{\cancel{10}^{(5}} = \frac{3}{2}$

$\frac{\cancel{{20}}^{(2}}{\cancel{24}^{(2}} = \frac{\cancel{{10}}^{(2}}{\cancel{12}^{(2}} = \frac{5}{6}$

$\frac{\cancel{{48}}^{(12}}{\cancel{72}^{(12}} = \frac{\cancel{{4}}^{(2}}{\cancel{6}^{(2}} = \frac{2}{3}$

$\frac{\cancel{{45}}^{(5}}{\cancel{150}^{(5}} = \frac{\cancel{{9}}^}{\cancel{50}}$

$\frac{\cancel{{63}}^{(7}}{\cancel{42}^{(7}} = \frac{\cancel{{9}}^{(3}}{\cancel{6}^{(3}} = \frac{3}{2}$

$\frac{\cancel{{200}}^{(10}}{\cancel{80}^{(10}} = \frac{\cancel{{20}}^{(4}}{\cancel{8}^{(4}} = \frac{5}{2}$

$\frac{\cancel{{285}}^{(95}}{\cancel{380}^{(95}} = \frac{3}{4}$

$\frac{\cancel{{396}}^{(99}}{\cancel{495}^{(99}} = \frac{4}{5}$

Answer 2

Răspuns:

Explicație pas cu pas:

(15/10)⁽⁵ = (15:5)/(10:5) = 3/2 - fracție ireductibilă

(20/24)⁽⁴ = (20:4)/(24:4) = 5/6

(48/72)⁽⁸ = (48:8)/(72:8) = (6/9)⁽³ = (6:3)/(9:3) = 2/3

(45/150)⁽⁵ =(45:5)/(150:5) = (9/30)⁽³ = (9:3)/(30:3) = 3/10

(63/42)⁽⁷ = (63:7)/(42:7) = (9/6)⁽³ = (9:3)/(6:3) = 3/2

(200/180)⁽²⁰ = (200:20)/(180:20) = 10/9

(285/380)⁽⁵ = (57/76)⁽¹⁹ = (57:19)/(76:19) = 3/4

(396/495)⁽³ = (132/165)⁽³ = (44/55)⁽¹¹ = (44:11)/(55:11) = 4/5