Question

Simplificati fractiile, astfel incat sa obtineti fractii ireductibile:
a) 12 supra 48
b) 210 supra 140
c) 5x3x7 supra 3x7x8
d) 2 la puterea a 2x3 la puterea 5 supra 2 la puterea 4x3 la puterea 2
e)625 supra 1750
f) 32a supra 40a
g)14a+14b supra 21a+21b
va rog frumos repede

Answer 1

a) 12/48=6/24=1/4
b)210/140=21/14=3/2
c)5x3x7/3x7x8=5x7/7x8=5/8
d)64 la puterea 5/4096 la puterea 2=1/64
e)625/1750=125/350=25/70=5/14
f)32a/40a=4/10=2/5
g)14a+14b/21a+21b=14(a+b)/21(a+b)=2/3