Question

Simplificati fractiile,astfel incat sa obtineti fractii ireductibile:20 supra 30;250 supra 350;2×3×7 supra 3×7×11;2la3 supra 2 la 5;2 la 7×3la2×5la4supra2la7×3la3×5la2×11;5200 supra18200;1716supra4290;72a supra108a;34a+34b supra 51 a+51 b.

Answer 1

Răspuns

Explicație pas cu pas:

20/30 = 2/3 (se simplifica cu 10)

250/350 = 25/35 = 5/7

2x3x7/3x7x11 = 2/11

2^3/2^5 = 1/2^2 = 1/4

2^7×3^2×5^4 / 2^7×3^3×5^2×11 = 5^2/3x11 = 25/33

5200/18200 = 52/182 = 26 / 91 =2/7

1716/4290 = 858/2145 = 286/715 = 22/55 = 2/5

72a/108a = 72/108 = 8/12 = 2/3

(34a+34b)/(51 a+51 b) = 34(a + b) / 51(a + b) = 34/51 = 2/3