Question

Simplificati fractiile, obținând fractii ireductibile:21supra49 36supra108 27supra72 5000supra7000 111supra159 820supra205

Answer 1

21/49 simplificam cu 7 = 3/7
36/108 simplificam cu 36 = 1/3
27/72 cu 9 = 3/8
5000/7000 cu 1000=5/7
111/159 cu 3=37/53
820/205 cu 205 = 4/1

Answer 2

   
[tex]\displaystyle \\ \frac{21}{49} = \frac{3 \times 7}{7 \times 7} = \frac{3 }{7} \\ \\ \frac{36}{108} = \frac{36}{3 \times 36} = \frac{1 }{3} \\ \\ \frac{27}{72} = \frac{3 \times 9}{8 \times 9} = \frac{3 }{8} \\ \\ \frac{5000}{7000} = \frac{5 \times 1000}{7 \times 1000} = \frac{5 }{7} \\ \\ \frac{111}{159} = \frac{37 \times 3}{53 \times 3} = \frac{37 }{53} \\ \\ \frac{820}{205} = \frac{4 \times 205}{205} = \frac{4 }{1} =4[/tex]