Question

simplificati fractiile urmatoare pana devin ireductibile:

6 supra 15, 24 supra 48, 9 supra 12, 8 supra 20, 12 supra 40, 36 supra 48, 100 supra 25, 49 supra42, 18 supra 240, 60 supra 75

Answer 1

$\frac{6}{15} = \frac{2}{5}$

$\frac{24}{48} = \frac{1}{2}$

$\frac{9}{12} = \frac{3}{4}$

$\frac{8}{20} = \frac{2}{5}$

$\frac{12}{40} = \frac{3}{10}$

$\frac{36}{48} = \frac{3}{4}$

$\frac{100}{25} = \frac{4}{1} = 4$

$\frac{49}{42} = \frac{7}{6}$

$\frac{18}{240} = \frac{3}{40}$

$\frac{60}{75} = \frac{4}{5}$