Question

Simplificați fracțiile următoare până devin ireductibile a 30 supra 12 b 28 supra 42 c 32 supra 40 D 45 supra 27 E 36 supra 48 f48 supra 54 G 475 supra 50 h80 supra 64 x 81 supra 54 j72supra90 k60supra84 l 84supra96​

Answer 1

Răspuns:

Vezi rezultatele mai jos:

Explicație pas cu pas:

$a) \frac{30}{12} = \frac{30:2}{12:2} = \frac{15:3}{6:3} = \frac{5}{2} \\\\b) \frac{28}{42} = \frac{28:2}{42:2} = \frac{14:7}{21:7} = \frac{2}{3} \\\\c) \frac{32}{40} = \frac{32:2}{40:2} = \frac{12:4}{20:5} = \frac{3}{5} \\\\d) \frac{45}{27} = \frac{45:3}{27:3} = \frac{15:3}{9:3} = \frac{5}{3} \\\\e) \frac{436}{48} = \frac{36:6}{48:6} = \frac{6:2}{8:2} = \frac{3}{4} \\\\f) \frac{48}{54} = \frac{48:6}{54:6} = \frac{8}{9}$$g) \frac{475}{50} = \frac{475:5}{50:5} = \frac{95:5}{10:2} = \frac{19}{2} \\\\h) \frac{80}{64} = \frac{80:8}{64:8} = \frac{10:2}{8:2} = \frac{5}{4} \\\\i) \frac{81}{54} = \frac{81:9}{54:9} = \frac{9:3}{6:3} = \frac{3}{2} \\\\j) \frac{72}{90} = \frac{72:9}{90:9} = \frac{8:2}{10:2} = \frac{4}{5} \\\\k) \frac{60}{84} = \frac{60:6}{84:6} = \frac{10:2}{14:2} = \frac{5}{7} \\\\l) \frac{84}{96} = \frac{84:6}{96:6} = \frac{14:2}{16:2} = \frac{7}{8}$