Question

Simplificati prin x+2 rapoartele :
2x+4 supra x^2-4

2x^2-8 supra x^2+4x+4

x^2+3x+2 supra x^2+2x

x^2-4 supra x^2+x-2

x^2-4x-12 supra x^2+5x+6

x^3+2x^3 supra x^3+8
2) 4-x^2 supra x^2+10x+16
Dau coroana!!!!

Answer 1

(2x+4)/x^2-4=2(x+2)/(x+2)(x-2) simplificand cu  x+2 se obtine 2/(x-2)
(2*x²-8)/(x²+4x+4)=2(x-2)(x+2)/(x+2)² simplificand cu x+2 se obtine 2(x-2)/x+2
(x²+3x+2)/(x²+2x)=(x²+x+2x+2)/x(x+2)=[x(x+1)+2(x+1)]/x(x+2)=(x+1)(x+2)/x(x+2) simplificand cu x+2 se obtine    (x+1)/x
(x²-4x-12)/(x²+5x+6)=(x²-6x+2x-12)/(x²+2x+3x+6)=[x(x-6)+2(x-6)]/[x(x+2)+3(x+2)]=(x-6)(x+2)/(x+2)(x+3) simplificand cu x+2 se obtine (x-6)/(x+3)
(x²-4)/(x²+x-2)=(x-2)(x+2)/(x²-x+2x-2)=(x-2)(x+2)/[x(x-1)+2(x-1)]=(x-2)(x+2)/(x-1)(x+2) simplificand cu x+2 se obtine (x-2)/(x-1)