Question

Simplificati prin x+3 raportul x+5x+6 supra x la a dua -9.

Answer 1

[tex] \frac{x^{2}+5x+6}{ x^{2} -9} = \frac{x^{2}+3x+2x+6}{(x-3)(x+3)} = \\ \frac{x(x+3)+2(x+3)}{(x-3)(x+3)} = \frac{(x+3)(x+2)}{(x+3)(x-3)} = \\ \frac{x+2}{x-3} [/tex]

Answer 2

$\frac{x patrat+2x+3x+6}{(x-3)(x+3)} = \frac{x(x+2)+3(x+2)}{(x-3)(x+3)} = \frac{(x+3)(x+2)}{(x-3)(x+3)}= \frac{x+2}{x-3}$

x²-9=x²-3²=(x+3)(x-3)