Question

Simplificati raportul 2x la puterea 2 -7x+3/xla puterea 2 -9 prim x-3.Va rog sa ma ajutati

Answer 1

[tex]\frac{2x^2-7x+3}{x^2-9}=\\ \frac{2x^2-6x-x+3}{x^2-9}=\\ \frac{2x(x-3)-(x-3)}{(x-3)(x+3)}=\\ \frac{(x-3)(2x-1)}{(x-3)(x+3)}=\frac{2x-1}{x+3}[/tex]