Question

Simplificati raportul 2x²-7x+3\x²-9 prin x-3,unde x este numar real,x≠ -3 si x≠3.

Answer 1

$\frac{ 2x^{2} - 7x + 3}{ x^{2} - 9} = \frac{2 x^{2} - 6x - x + 3}{ x^{2} - 9} =$

$= \frac{2x(x - 3) -(x - 3)}{(x - 3)(x + 3)} = \frac{(x - 3)(2x - 1)}{(x - 3)(x + 3)} = \frac{2x - 1}{x + 3}$