Question

Simplificati raportul x²+3x+2 supra x²-4, x∈R\{-2,2}

Answer 1

$\frac{x^2+3x+2}{x^2-4}= \frac{x^2+2x+x+2}{(x+2)(x-2)} = \frac{x(x+2)+x+2}{(x+2)(x-2)} = \frac{(x+2)(x+1)}{(x+2)(x-2)}= \frac{x+1}{x-2}$