Question

Simplificati $\frac{2+4+6+...+200}{3+6+9+...+300}$

Answer 1

$\frac{2+4+6+.....+200}{3+6+9+.....+300}=\frac{2*(1+2+3+......+100)}{3*(1+2+3+......+100)}=\frac{2}{3}$