Question

simplificati urmatoare : 3^34/3^35; 25^7/125^17; 2^33+2^33/2^33;4^25+8^17/2^52-16^12; 2^4+3^4/194^2

Answer 1

3^34/3^35 =1/3
25^7/125^17=5^14/5^51=1/5^37
(2^33+2^33)/2^33=2^33(2^0+2^0)/2^33=2^33(1+1)/2^33=2^33*2/2^33=2
(4^25+8^17)/(2^52-16^12)=(2^50+2^51)/(2^52-2^48)=
=2^50(2^0+2^1)/2^48(2^4-2^0)=
=2^50(1+2)/2^48(16-1)=
=2^50*3/2^48*15=
=2^2/5=4/5
 (2^4+3^4)/194^2=
=(16+81)/194^2=97/194^2=97/2^2 *97^2=1/4*97=1/388