Question

Simplificati urmatoarele fractii, obtinand fractii ireductibile : 36/108, 52/78, 99/8181, 39/16, 40/320, 14/49, 72/84, 180/720, 2002/7 x 11 x 13, 256/2 la puterea 7 x 3

Answer 1

36/108 cu 36=1/3
 52/78 cu 2 = 26/39
99/8181 cu 3=33/2727 cu 3= 11/909
39/16 nu se simplifica
40/320 cu 40 = 1/8
14/49 cu 7=2/7
180/720 cu 180=1/4
 2002/7x11x13= 2002/1001 cu 1001=2/1
256/2 la 21 = 1/8192