Question

simplificati urmatoarele fractii pana devin fractii ireductibile:
25/35
8/36
4/20
8/16
8/12
12/15
4/28
12/27
35/45
va rog ajutor​

Answer 1

Răspuns:

a)25/35(cu 5)=5/7

b)8/36(cu 4)=2/9

c)4/20(cu 2)= 1/5

d)8/16(cu 8)=1/2

e)12/15(cu 3)=4/5

f)4/28(cu 4)= 1/7

g)12/27(cu 3)=4/9

h)35/45(cu 5)=7/9

Answer 2

Am facut poza la raspuns