Question

Simplificati urmatoarele fractii pana obtineti fractii ireductibile:7*2 la 50+3*2 la 51 supra 4*3 la 50 +3 la 52 ; 3 la n +2*3 la n+1 + 3 la n+2 supra 2*5 la n +5 la n +1 +5 la n+2

Answer 1

(7×2⁵⁰+3×2⁵¹)/(4×3⁵⁰ +3⁵² )=
=2⁵⁰(7+3×2¹)/3⁵⁰(4+3² )=
=2⁵⁰(7+6)/3⁵⁰(4+9 )=
=2⁵⁰×13/3⁵⁰×13=
=(2/3)⁵⁰

( 3ⁿ +2×3 ⁿ⁺¹ + 3ⁿ⁺²)/(2×5ⁿ +5 ⁿ⁺¹ +5 ⁿ⁺²)=
= 3ⁿ(1+2×3¹ + 3²)/5ⁿ(2*1 +5¹ +5²)=
= 3ⁿ(1+6 + 9)/5ⁿ(2 +5 +25)=
= 3ⁿ×16/5ⁿ×32=
= 3ⁿ/(5ⁿ×2)