Question

Simplificatiurmatoarele fractiipentru a obtine fractiiireductibile: 7x+14y/3x+6y,5a-15b/10a-30b, 6x+24y/8x+32y​

Answer 1

Răspuns:

Explicație pas cu pas:

7x + 14y = 7*(x + 2y)

3x + 6y = 3*(x + 2y)

fractia 7*(x + 2y)/3*(x + 2y) se simplifica cu x + 2y si devine 7/3

_________

5a - 15b = 5*(a - 3b)

10a - 30b = 10*(a - 3b)

5*(a - 3b)/10*(a - 3b) = 5/10 = 1/2

_________

6x + 24y = 6*(x + 4y)

8x + 32y = 8*(x + 4y)

6*(x + 4y)/8*(x + 4y) = 6/8 = 3/4